3*10^(2y)=3,600

Solution for 3*10^(2y)=3,600 equation:

3*10^(2y)=3.600

We move all terms to the left:

3*10^(2y)-(3.600)=0

We add all the numbers together, and all the variables

3*10^2y-(3.6)=0

We add all the numbers together, and all the variables

3*10^2y-3.6=0

Wy multiply elements

30y^2-3.6=0

a = 30; b = 0; c = -3.6;
Δ = b2-4ac
Δ = 02-4·30·(-3.6)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*30}=\frac{0-12\sqrt{3}}{60}
=-\frac{12\sqrt{3}}{60}
=-\frac{\sqrt{3}}{5}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*30}=\frac{0+12\sqrt{3}}{60}
=\frac{12\sqrt{3}}{60}
=\frac{\sqrt{3}}{5}
$